Metamath Proof Explorer


Theorem ssuni

Description: Subclass relationship for class union. (Contributed by NM, 24-May-1994) (Proof shortened by Andrew Salmon, 29-Jun-2011) (Proof shortened by JJ, 26-Jul-2021)

Ref Expression
Assertion ssuni ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ∈ 𝐶 ) → 𝐴 ⊆ ∪ 𝐶 )

Proof

Step Hyp Ref Expression
1 elunii ⊢ ( ( 𝑥 ∈ 𝐵 ∧ 𝐵 ∈ 𝐶 ) → 𝑥 ∈ ∪ 𝐶 )
2 1 expcom ⊢ ( 𝐵 ∈ 𝐶 → ( 𝑥 ∈ 𝐵 → 𝑥 ∈ ∪ 𝐶 ) )
3 2 imim2d ⊢ ( 𝐵 ∈ 𝐶 → ( ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) → ( 𝑥 ∈ 𝐴 → 𝑥 ∈ ∪ 𝐶 ) ) )
4 3 alimdv ⊢ ( 𝐵 ∈ 𝐶 → ( ∀ 𝑥 ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) → ∀ 𝑥 ( 𝑥 ∈ 𝐴 → 𝑥 ∈ ∪ 𝐶 ) ) )
5 df-ss ⊢ ( 𝐴 ⊆ 𝐵 ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐴 → 𝑥 ∈ 𝐵 ) )
6 df-ss ⊢ ( 𝐴 ⊆ ∪ 𝐶 ↔ ∀ 𝑥 ( 𝑥 ∈ 𝐴 → 𝑥 ∈ ∪ 𝐶 ) )
7 4 5 6 3imtr4g ⊢ ( 𝐵 ∈ 𝐶 → ( 𝐴 ⊆ 𝐵 → 𝐴 ⊆ ∪ 𝐶 ) )
8 7 impcom ⊢ ( ( 𝐴 ⊆ 𝐵 ∧ 𝐵 ∈ 𝐶 ) → 𝐴 ⊆ ∪ 𝐶 )