Metamath Proof Explorer


Theorem stcltrthi

Description: Theorem for classically strong set of states. If there exists a "classically strong set of states" on lattice CH (or actually any ortholattice, which would have an identical proof), then any two elements of the lattice commute, i.e., the lattice is distributive. (Proof due to Mladen Pavicic.) Theorem 3.3 of MegPav2000 p. 2344. (Contributed by NM, 24-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypotheses stcltrth.1 𝐴C
stcltrth.2 𝐵C
stcltrth.3 𝑠 ∈ States ∀ 𝑥C𝑦C ( ( ( 𝑠𝑥 ) = 1 → ( 𝑠𝑦 ) = 1 ) → 𝑥𝑦 )
Assertion stcltrthi 𝐵 ⊆ ( ( ⊥ ‘ 𝐴 ) ∨ ( 𝐴𝐵 ) )

Proof

Step Hyp Ref Expression
1 stcltrth.1 𝐴C
2 stcltrth.2 𝐵C
3 stcltrth.3 𝑠 ∈ States ∀ 𝑥C𝑦C ( ( ( 𝑠𝑥 ) = 1 → ( 𝑠𝑦 ) = 1 ) → 𝑥𝑦 )
4 biid ( ( 𝑠 ∈ States ∧ ∀ 𝑥C𝑦C ( ( ( 𝑠𝑥 ) = 1 → ( 𝑠𝑦 ) = 1 ) → 𝑥𝑦 ) ) ↔ ( 𝑠 ∈ States ∧ ∀ 𝑥C𝑦C ( ( ( 𝑠𝑥 ) = 1 → ( 𝑠𝑦 ) = 1 ) → 𝑥𝑦 ) ) )
5 4 1 2 stcltrlem2 ( ( 𝑠 ∈ States ∧ ∀ 𝑥C𝑦C ( ( ( 𝑠𝑥 ) = 1 → ( 𝑠𝑦 ) = 1 ) → 𝑥𝑦 ) ) → 𝐵 ⊆ ( ( ⊥ ‘ 𝐴 ) ∨ ( 𝐴𝐵 ) ) )
6 5 rexlimiva ( ∃ 𝑠 ∈ States ∀ 𝑥C𝑦C ( ( ( 𝑠𝑥 ) = 1 → ( 𝑠𝑦 ) = 1 ) → 𝑥𝑦 ) → 𝐵 ⊆ ( ( ⊥ ‘ 𝐴 ) ∨ ( 𝐴𝐵 ) ) )
7 3 6 ax-mp 𝐵 ⊆ ( ( ⊥ ‘ 𝐴 ) ∨ ( 𝐴𝐵 ) )