Metamath Proof Explorer


Theorem subrngbas

Description: Base set of a subring structure. (Contributed by AV, 14-Feb-2025)

Ref Expression
Hypothesis subrng0.1 𝑆 = ( 𝑅s 𝐴 )
Assertion subrngbas ( 𝐴 ∈ ( SubRng ‘ 𝑅 ) → 𝐴 = ( Base ‘ 𝑆 ) )

Proof

Step Hyp Ref Expression
1 subrng0.1 𝑆 = ( 𝑅s 𝐴 )
2 subrngsubg ( 𝐴 ∈ ( SubRng ‘ 𝑅 ) → 𝐴 ∈ ( SubGrp ‘ 𝑅 ) )
3 1 subgbas ( 𝐴 ∈ ( SubGrp ‘ 𝑅 ) → 𝐴 = ( Base ‘ 𝑆 ) )
4 2 3 syl ( 𝐴 ∈ ( SubRng ‘ 𝑅 ) → 𝐴 = ( Base ‘ 𝑆 ) )