Metamath Proof Explorer


Theorem syl5eq

Description: An equality transitivity deduction. (Contributed by NM, 21-Jun-1993)

Ref Expression
Hypotheses syl5eq.1 𝐴 = 𝐵
syl5eq.2 ( 𝜑𝐵 = 𝐶 )
Assertion syl5eq ( 𝜑𝐴 = 𝐶 )

Proof

Step Hyp Ref Expression
1 syl5eq.1 𝐴 = 𝐵
2 syl5eq.2 ( 𝜑𝐵 = 𝐶 )
3 1 a1i ( 𝜑𝐴 = 𝐵 )
4 3 2 eqtrd ( 𝜑𝐴 = 𝐶 )