Metamath Proof Explorer


Theorem t1sncld

Description: In a T_1 space, singletons are closed. (Contributed by Jeff Hankins, 1-Feb-2010)

Ref Expression
Hypothesis ist0.1 ⊢ 𝑋 = ∪ 𝐽
Assertion t1sncld ( ( 𝐽 ∈ Fre ∧ 𝐴 ∈ 𝑋 ) → { 𝐴 } ∈ ( Clsd ‘ 𝐽 ) )

Proof

Step Hyp Ref Expression
1 ist0.1 ⊢ 𝑋 = ∪ 𝐽
2 1 ist1 ⊢ ( 𝐽 ∈ Fre ↔ ( 𝐽 ∈ Top ∧ ∀ 𝑥 ∈ 𝑋 { 𝑥 } ∈ ( Clsd ‘ 𝐽 ) ) )
3 sneq ⊢ ( 𝑥 = 𝐴 → { 𝑥 } = { 𝐴 } )
4 3 eleq1d ⊢ ( 𝑥 = 𝐴 → ( { 𝑥 } ∈ ( Clsd ‘ 𝐽 ) ↔ { 𝐴 } ∈ ( Clsd ‘ 𝐽 ) ) )
5 4 rspccv ⊢ ( ∀ 𝑥 ∈ 𝑋 { 𝑥 } ∈ ( Clsd ‘ 𝐽 ) → ( 𝐴 ∈ 𝑋 → { 𝐴 } ∈ ( Clsd ‘ 𝐽 ) ) )
6 2 5 simplbiim ⊢ ( 𝐽 ∈ Fre → ( 𝐴 ∈ 𝑋 → { 𝐴 } ∈ ( Clsd ‘ 𝐽 ) ) )
7 6 imp ⊢ ( ( 𝐽 ∈ Fre ∧ 𝐴 ∈ 𝑋 ) → { 𝐴 } ∈ ( Clsd ‘ 𝐽 ) )