Metamath Proof Explorer


Theorem thincinv

Description: In a thin category, F is an inverse of G iff F is a section of G . Example 7.20(7) of Adamek p. 107. (Contributed by Zhi Wang, 24-Sep-2024)

Ref Expression
Hypotheses thincsect.c ⊢ ( 𝜑 → 𝐶 ∈ ThinCat )
thincsect.b ⊢ 𝐵 = ( Base ‘ 𝐶 )
thincsect.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
thincsect.y ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
thincsect.s ⊢ 𝑆 = ( Sect ‘ 𝐶 )
thincinv.n ⊢ 𝑁 = ( Inv ‘ 𝐶 )
Assertion thincinv ( 𝜑 → ( 𝐹 ( 𝑋 𝑁 𝑌 ) 𝐺 ↔ 𝐹 ( 𝑋 𝑆 𝑌 ) 𝐺 ) )

Proof

Step Hyp Ref Expression
1 thincsect.c ⊢ ( 𝜑 → 𝐶 ∈ ThinCat )
2 thincsect.b ⊢ 𝐵 = ( Base ‘ 𝐶 )
3 thincsect.x ⊢ ( 𝜑 → 𝑋 ∈ 𝐵 )
4 thincsect.y ⊢ ( 𝜑 → 𝑌 ∈ 𝐵 )
5 thincsect.s ⊢ 𝑆 = ( Sect ‘ 𝐶 )
6 thincinv.n ⊢ 𝑁 = ( Inv ‘ 𝐶 )
7 1 thinccatd ⊢ ( 𝜑 → 𝐶 ∈ Cat )
8 2 6 7 3 4 5 isinv ⊢ ( 𝜑 → ( 𝐹 ( 𝑋 𝑁 𝑌 ) 𝐺 ↔ ( 𝐹 ( 𝑋 𝑆 𝑌 ) 𝐺 ∧ 𝐺 ( 𝑌 𝑆 𝑋 ) 𝐹 ) ) )
9 1 2 3 4 5 thincsect2 ⊢ ( 𝜑 → ( 𝐹 ( 𝑋 𝑆 𝑌 ) 𝐺 ↔ 𝐺 ( 𝑌 𝑆 𝑋 ) 𝐹 ) )
10 9 biimpa ⊢ ( ( 𝜑 ∧ 𝐹 ( 𝑋 𝑆 𝑌 ) 𝐺 ) → 𝐺 ( 𝑌 𝑆 𝑋 ) 𝐹 )
11 8 10 mpbiran3d ⊢ ( 𝜑 → ( 𝐹 ( 𝑋 𝑁 𝑌 ) 𝐺 ↔ 𝐹 ( 𝑋 𝑆 𝑌 ) 𝐺 ) )