Metamath Proof Explorer


Theorem tskss

Description: The subsets of an element of a Tarski class belong to the class. (Contributed by FL, 30-Dec-2010) (Revised by Mario Carneiro, 18-Jun-2013)

Ref Expression
Assertion tskss ( ( 𝑇 ∈ Tarski ∧ 𝐴 ∈ 𝑇 ∧ 𝐵 ⊆ 𝐴 ) → 𝐵 ∈ 𝑇 )

Proof

Step Hyp Ref Expression
1 elpw2g ⊢ ( 𝐴 ∈ 𝑇 → ( 𝐵 ∈ 𝒫 𝐴 ↔ 𝐵 ⊆ 𝐴 ) )
2 1 adantl ⊢ ( ( 𝑇 ∈ Tarski ∧ 𝐴 ∈ 𝑇 ) → ( 𝐵 ∈ 𝒫 𝐴 ↔ 𝐵 ⊆ 𝐴 ) )
3 tskpwss ⊢ ( ( 𝑇 ∈ Tarski ∧ 𝐴 ∈ 𝑇 ) → 𝒫 𝐴 ⊆ 𝑇 )
4 3 sseld ⊢ ( ( 𝑇 ∈ Tarski ∧ 𝐴 ∈ 𝑇 ) → ( 𝐵 ∈ 𝒫 𝐴 → 𝐵 ∈ 𝑇 ) )
5 2 4 sylbird ⊢ ( ( 𝑇 ∈ Tarski ∧ 𝐴 ∈ 𝑇 ) → ( 𝐵 ⊆ 𝐴 → 𝐵 ∈ 𝑇 ) )
6 5 3impia ⊢ ( ( 𝑇 ∈ Tarski ∧ 𝐴 ∈ 𝑇 ∧ 𝐵 ⊆ 𝐴 ) → 𝐵 ∈ 𝑇 )