Metamath Proof Explorer


Theorem ttcuniun

Description: Relationship between TC+ A and TC+ U. A : we can decompose TC+ A into the elements of TC+ U. A plus the elements of A itself. (Contributed by Matthew House, 6-Apr-2026)

Ref Expression
Assertion ttcuniun TC+ 𝐴 = ( TC+ 𝐴𝐴 )

Proof

Step Hyp Ref Expression
1 ssun2 𝐴 ⊆ ( TC+ 𝐴𝐴 )
2 uniun ( TC+ 𝐴𝐴 ) = ( TC+ 𝐴 𝐴 )
3 ttctr3 TC+ 𝐴 ⊆ TC+ 𝐴
4 ttcid 𝐴 ⊆ TC+ 𝐴
5 3 4 unssi ( TC+ 𝐴 𝐴 ) ⊆ TC+ 𝐴
6 2 5 eqsstri ( TC+ 𝐴𝐴 ) ⊆ TC+ 𝐴
7 ssun3 ( ( TC+ 𝐴𝐴 ) ⊆ TC+ 𝐴 ( TC+ 𝐴𝐴 ) ⊆ ( TC+ 𝐴𝐴 ) )
8 6 7 ax-mp ( TC+ 𝐴𝐴 ) ⊆ ( TC+ 𝐴𝐴 )
9 df-tr ( Tr ( TC+ 𝐴𝐴 ) ↔ ( TC+ 𝐴𝐴 ) ⊆ ( TC+ 𝐴𝐴 ) )
10 8 9 mpbir Tr ( TC+ 𝐴𝐴 )
11 ttcmin ( ( 𝐴 ⊆ ( TC+ 𝐴𝐴 ) ∧ Tr ( TC+ 𝐴𝐴 ) ) → TC+ 𝐴 ⊆ ( TC+ 𝐴𝐴 ) )
12 1 10 11 mp2an TC+ 𝐴 ⊆ ( TC+ 𝐴𝐴 )
13 ttcid 𝐴 ⊆ TC+ 𝐴
14 13 unissi 𝐴 TC+ 𝐴
15 ttctr3 TC+ 𝐴 ⊆ TC+ 𝐴
16 14 15 sstri 𝐴 ⊆ TC+ 𝐴
17 ttcss ( 𝐴 ⊆ TC+ 𝐴 → TC+ 𝐴 ⊆ TC+ 𝐴 )
18 16 17 ax-mp TC+ 𝐴 ⊆ TC+ 𝐴
19 18 13 unssi ( TC+ 𝐴𝐴 ) ⊆ TC+ 𝐴
20 12 19 eqssi TC+ 𝐴 = ( TC+ 𝐴𝐴 )