Metamath Proof Explorer


Theorem unieqd

Description: Deduction of equality of two class unions. (Contributed by NM, 21-Apr-1995)

Ref Expression
Hypothesis unieqd.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
Assertion unieqd ( 𝜑 → ∪ 𝐴 = ∪ 𝐵 )

Proof

Step Hyp Ref Expression
1 unieqd.1 ⊢ ( 𝜑 → 𝐴 = 𝐵 )
2 unieq ⊢ ( 𝐴 = 𝐵 → ∪ 𝐴 = ∪ 𝐵 )
3 1 2 syl ⊢ ( 𝜑 → ∪ 𝐴 = ∪ 𝐵 )