Metamath Proof Explorer


Theorem unisym1

Description: A symmetry with A. .

See negsym1 for more information. (Contributed by Anthony Hart, 4-Sep-2011) (Proof shortened by Mario Carneiro, 11-Dec-2016)

Ref Expression
Assertion unisym1 ( ∀ 𝑥𝑥 ⊥ → ∀ 𝑥 𝜑 )

Proof

Step Hyp Ref Expression
1 falim ( ⊥ → ∀ 𝑥 𝜑 )
2 1 sps ( ∀ 𝑥 ⊥ → ∀ 𝑥 𝜑 )
3 2 sps ( ∀ 𝑥𝑥 ⊥ → ∀ 𝑥 𝜑 )