Metamath Proof Explorer


Theorem unitg

Description: The topology generated by a basis B is a topology on U. B . Importantly, this theorem means that we don't have to specify separately the base set for the topological space generated by a basis. In other words, any member of the class TopBases completely specifies the basis it corresponds to. (Contributed by NM, 16-Jul-2006) (Proof shortened by OpenAI, 30-Mar-2020)

Ref Expression
Assertion unitg ( 𝐵 ∈ 𝑉 → ∪ ( topGen ‘ 𝐵 ) = ∪ 𝐵 )

Proof

Step Hyp Ref Expression
1 tg1 ⊢ ( 𝑥 ∈ ( topGen ‘ 𝐵 ) → 𝑥 ⊆ ∪ 𝐵 )
2 velpw ⊢ ( 𝑥 ∈ 𝒫 ∪ 𝐵 ↔ 𝑥 ⊆ ∪ 𝐵 )
3 1 2 sylibr ⊢ ( 𝑥 ∈ ( topGen ‘ 𝐵 ) → 𝑥 ∈ 𝒫 ∪ 𝐵 )
4 3 ssriv ⊢ ( topGen ‘ 𝐵 ) ⊆ 𝒫 ∪ 𝐵
5 sspwuni ⊢ ( ( topGen ‘ 𝐵 ) ⊆ 𝒫 ∪ 𝐵 ↔ ∪ ( topGen ‘ 𝐵 ) ⊆ ∪ 𝐵 )
6 4 5 mpbi ⊢ ∪ ( topGen ‘ 𝐵 ) ⊆ ∪ 𝐵
7 6 a1i ⊢ ( 𝐵 ∈ 𝑉 → ∪ ( topGen ‘ 𝐵 ) ⊆ ∪ 𝐵 )
8 bastg ⊢ ( 𝐵 ∈ 𝑉 → 𝐵 ⊆ ( topGen ‘ 𝐵 ) )
9 8 unissd ⊢ ( 𝐵 ∈ 𝑉 → ∪ 𝐵 ⊆ ∪ ( topGen ‘ 𝐵 ) )
10 7 9 eqssd ⊢ ( 𝐵 ∈ 𝑉 → ∪ ( topGen ‘ 𝐵 ) = ∪ 𝐵 )