Metamath Proof Explorer


Theorem up1st2ndr

Description: Combine separated parts in the universal property predicate. (Contributed by Zhi Wang, 23-Oct-2025)

Ref Expression
Hypotheses up1st2ndr.1 ( 𝜑𝐹 ∈ ( 𝐷 Func 𝐸 ) )
up1st2ndr.2 ( 𝜑𝑋 ( ⟨ ( 1st𝐹 ) , ( 2nd𝐹 ) ⟩ ( 𝐷 UP 𝐸 ) 𝑊 ) 𝑀 )
Assertion up1st2ndr ( 𝜑𝑋 ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) 𝑀 )

Proof

Step Hyp Ref Expression
1 up1st2ndr.1 ( 𝜑𝐹 ∈ ( 𝐷 Func 𝐸 ) )
2 up1st2ndr.2 ( 𝜑𝑋 ( ⟨ ( 1st𝐹 ) , ( 2nd𝐹 ) ⟩ ( 𝐷 UP 𝐸 ) 𝑊 ) 𝑀 )
3 relfunc Rel ( 𝐷 Func 𝐸 )
4 1st2nd ( ( Rel ( 𝐷 Func 𝐸 ) ∧ 𝐹 ∈ ( 𝐷 Func 𝐸 ) ) → 𝐹 = ⟨ ( 1st𝐹 ) , ( 2nd𝐹 ) ⟩ )
5 3 1 4 sylancr ( 𝜑𝐹 = ⟨ ( 1st𝐹 ) , ( 2nd𝐹 ) ⟩ )
6 5 oveq1d ( 𝜑 → ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) = ( ⟨ ( 1st𝐹 ) , ( 2nd𝐹 ) ⟩ ( 𝐷 UP 𝐸 ) 𝑊 ) )
7 6 eqcomd ( 𝜑 → ( ⟨ ( 1st𝐹 ) , ( 2nd𝐹 ) ⟩ ( 𝐷 UP 𝐸 ) 𝑊 ) = ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) )
8 7 2 breqdi ( 𝜑𝑋 ( 𝐹 ( 𝐷 UP 𝐸 ) 𝑊 ) 𝑀 )