Metamath Proof Explorer
		
		
		
		Description:  If all vertices in a simple graph have the same degree, the graph is
       k-regular.  (Contributed by AV, 26-Dec-2020)
		
			
				
					|  |  | Ref | Expression | 
					
						|  | Hypotheses | isrusgr0.v | ⊢ 𝑉  =  ( Vtx ‘ 𝐺 ) | 
					
						|  |  | isrusgr0.d | ⊢ 𝐷  =  ( VtxDeg ‘ 𝐺 ) | 
				
					|  | Assertion | usgreqdrusgr | ⊢  ( ( 𝐺  ∈  USGraph  ∧  𝐾  ∈  ℕ0*  ∧  ∀ 𝑣  ∈  𝑉 ( 𝐷 ‘ 𝑣 )  =  𝐾 )  →  𝐺  RegUSGraph  𝐾 ) | 
			
		
		
			
				Proof
				
					
						| Step | Hyp | Ref | Expression | 
						
							| 1 |  | isrusgr0.v | ⊢ 𝑉  =  ( Vtx ‘ 𝐺 ) | 
						
							| 2 |  | isrusgr0.d | ⊢ 𝐷  =  ( VtxDeg ‘ 𝐺 ) | 
						
							| 3 | 1 2 | isrusgr0 | ⊢ ( ( 𝐺  ∈  USGraph  ∧  𝐾  ∈  ℕ0* )  →  ( 𝐺  RegUSGraph  𝐾  ↔  ( 𝐺  ∈  USGraph  ∧  𝐾  ∈  ℕ0*  ∧  ∀ 𝑣  ∈  𝑉 ( 𝐷 ‘ 𝑣 )  =  𝐾 ) ) ) | 
						
							| 4 | 3 | 3adant3 | ⊢ ( ( 𝐺  ∈  USGraph  ∧  𝐾  ∈  ℕ0*  ∧  ∀ 𝑣  ∈  𝑉 ( 𝐷 ‘ 𝑣 )  =  𝐾 )  →  ( 𝐺  RegUSGraph  𝐾  ↔  ( 𝐺  ∈  USGraph  ∧  𝐾  ∈  ℕ0*  ∧  ∀ 𝑣  ∈  𝑉 ( 𝐷 ‘ 𝑣 )  =  𝐾 ) ) ) | 
						
							| 5 | 4 | ibir | ⊢ ( ( 𝐺  ∈  USGraph  ∧  𝐾  ∈  ℕ0*  ∧  ∀ 𝑣  ∈  𝑉 ( 𝐷 ‘ 𝑣 )  =  𝐾 )  →  𝐺  RegUSGraph  𝐾 ) |