Metamath Proof Explorer


Theorem vtoclga

Description: Implicit substitution of a class for a setvar variable. (Contributed by NM, 20-Aug-1995) Avoid ax-10 and ax-11 . (Revised by GG, 20-Aug-2023)

Ref Expression
Hypotheses vtoclga.1 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
vtoclga.2 ⊢ ( 𝑥 ∈ 𝐵 → 𝜑 )
Assertion vtoclga ( 𝐴 ∈ 𝐵 → 𝜓 )

Proof

Step Hyp Ref Expression
1 vtoclga.1 ⊢ ( 𝑥 = 𝐴 → ( 𝜑 ↔ 𝜓 ) )
2 vtoclga.2 ⊢ ( 𝑥 ∈ 𝐵 → 𝜑 )
3 eleq1 ⊢ ( 𝑥 = 𝐴 → ( 𝑥 ∈ 𝐵 ↔ 𝐴 ∈ 𝐵 ) )
4 3 1 imbi12d ⊢ ( 𝑥 = 𝐴 → ( ( 𝑥 ∈ 𝐵 → 𝜑 ) ↔ ( 𝐴 ∈ 𝐵 → 𝜓 ) ) )
5 4 2 vtoclg ⊢ ( 𝐴 ∈ 𝐵 → ( 𝐴 ∈ 𝐵 → 𝜓 ) )
6 5 pm2.43i ⊢ ( 𝐴 ∈ 𝐵 → 𝜓 )