Metamath Proof Explorer


Theorem wrddin2

Description: Distribution of word class constructor over class intersection. (Contributed by Ender Ting, 24-Jul-2026)

Ref Expression
Assertion wrddin2 Word ( 𝐵𝐶 ) = ( Word 𝐵 ∩ Word 𝐶 )

Proof

Step Hyp Ref Expression
1 wrddrin ( 𝑛 ∈ Word ( 𝐵𝐶 ) → ( 𝑛 ∈ Word 𝐵𝑛 ∈ Word 𝐶 ) )
2 wrddin ( ( 𝑛 ∈ Word 𝐵𝑛 ∈ Word 𝐶 ) → 𝑛 ∈ Word ( 𝐵𝐶 ) )
3 1 2 impbii ( 𝑛 ∈ Word ( 𝐵𝐶 ) ↔ ( 𝑛 ∈ Word 𝐵𝑛 ∈ Word 𝐶 ) )
4 elin ( 𝑛 ∈ ( Word 𝐵 ∩ Word 𝐶 ) ↔ ( 𝑛 ∈ Word 𝐵𝑛 ∈ Word 𝐶 ) )
5 3 4 bitr4i ( 𝑛 ∈ Word ( 𝐵𝐶 ) ↔ 𝑛 ∈ ( Word 𝐵 ∩ Word 𝐶 ) )
6 5 eqriv Word ( 𝐵𝐶 ) = ( Word 𝐵 ∩ Word 𝐶 )