Metamath Proof Explorer


Theorem xpid11

Description: The Cartesian square is a one-to-one construction. (Contributed by NM, 5-Nov-2006) (Proof shortened by Andrew Salmon, 27-Aug-2011)

Ref Expression
Assertion xpid11 ( ( 𝐴 × 𝐴 ) = ( 𝐵 × 𝐵 ) ↔ 𝐴 = 𝐵 )

Proof

Step Hyp Ref Expression
1 dmeq ⊢ ( ( 𝐴 × 𝐴 ) = ( 𝐵 × 𝐵 ) → dom ( 𝐴 × 𝐴 ) = dom ( 𝐵 × 𝐵 ) )
2 dmxpid ⊢ dom ( 𝐴 × 𝐴 ) = 𝐴
3 dmxpid ⊢ dom ( 𝐵 × 𝐵 ) = 𝐵
4 1 2 3 3eqtr3g ⊢ ( ( 𝐴 × 𝐴 ) = ( 𝐵 × 𝐵 ) → 𝐴 = 𝐵 )
5 xpeq12 ⊢ ( ( 𝐴 = 𝐵 ∧ 𝐴 = 𝐵 ) → ( 𝐴 × 𝐴 ) = ( 𝐵 × 𝐵 ) )
6 5 anidms ⊢ ( 𝐴 = 𝐵 → ( 𝐴 × 𝐴 ) = ( 𝐵 × 𝐵 ) )
7 4 6 impbii ⊢ ( ( 𝐴 × 𝐴 ) = ( 𝐵 × 𝐵 ) ↔ 𝐴 = 𝐵 )