Metamath Proof Explorer
Description: Equality theorem for the range Cartesian product, deduction form.
(Contributed by Peter Mazsa, 18-Dec-2021)
|
|
Ref |
Expression |
|
Hypotheses |
xrneq12d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
|
|
xrneq12d.2 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
|
Assertion |
xrneq12d |
⊢ ( 𝜑 → ( 𝐴 ⋉ 𝐶 ) = ( 𝐵 ⋉ 𝐷 ) ) |
Proof
| Step |
Hyp |
Ref |
Expression |
| 1 |
|
xrneq12d.1 |
⊢ ( 𝜑 → 𝐴 = 𝐵 ) |
| 2 |
|
xrneq12d.2 |
⊢ ( 𝜑 → 𝐶 = 𝐷 ) |
| 3 |
|
xrneq12 |
⊢ ( ( 𝐴 = 𝐵 ∧ 𝐶 = 𝐷 ) → ( 𝐴 ⋉ 𝐶 ) = ( 𝐵 ⋉ 𝐷 ) ) |
| 4 |
1 2 3
|
syl2anc |
⊢ ( 𝜑 → ( 𝐴 ⋉ 𝐶 ) = ( 𝐵 ⋉ 𝐷 ) ) |