Theorem 3expib

Description: Exportation from triple conjunction. (Contributed by NM, 19-May-2007)

	Ref	Expression
Hypothesis	3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
Assertion	3expib	|- ( ph -> ( ( ps /\ ch ) -> th ) )

Proof

Step	Hyp	Ref	Expression
1		3exp.1	|- ( ( ph /\ ps /\ ch ) -> th )
2	1	3exp	|- ( ph -> ( ps -> ( ch -> th ) ) )
3	2	impd	|- ( ph -> ( ( ps /\ ch ) -> th ) )