Metamath Proof Explorer


Theorem aiotaint

Description: This is to df-aiota what iotauni is to df-iota (it uses intersection like df-aiota , similar to iotauni using union like df-iota ; we could also prove an analogous result using union here too, in the same way that we have iotaint ). (Contributed by BJ, 31-Aug-2024)

Ref Expression
Assertion aiotaint
|- ( E! x ph -> ( iota' x ph ) = |^| { x | ph } )

Proof

Step Hyp Ref Expression
1 reuaiotaiota
 |-  ( E! x ph <-> ( iota x ph ) = ( iota' x ph ) )
2 1 biimpi
 |-  ( E! x ph -> ( iota x ph ) = ( iota' x ph ) )
3 iotaint
 |-  ( E! x ph -> ( iota x ph ) = |^| { x | ph } )
4 2 3 eqtr3d
 |-  ( E! x ph -> ( iota' x ph ) = |^| { x | ph } )