Metamath Proof Explorer


Theorem aiotaint

Description: This is to df-aiota what iotauni is to df-iota (it uses intersection like df-aiota , similar to iotauni using union like df-iota ; we could also prove an analogous result using union here too, in the same way that we have iotaint ). (Contributed by BJ, 31-Aug-2024)

Ref Expression
Assertion aiotaint ( ∃! 𝑥 𝜑 → ( ℩' 𝑥 𝜑 ) = ∩ { 𝑥 ∣ 𝜑 } )

Proof

Step Hyp Ref Expression
1 reuaiotaiota ⊢ ( ∃! 𝑥 𝜑 ↔ ( ℩ 𝑥 𝜑 ) = ( ℩' 𝑥 𝜑 ) )
2 1 biimpi ⊢ ( ∃! 𝑥 𝜑 → ( ℩ 𝑥 𝜑 ) = ( ℩' 𝑥 𝜑 ) )
3 iotaint ⊢ ( ∃! 𝑥 𝜑 → ( ℩ 𝑥 𝜑 ) = ∩ { 𝑥 ∣ 𝜑 } )
4 2 3 eqtr3d ⊢ ( ∃! 𝑥 𝜑 → ( ℩' 𝑥 𝜑 ) = ∩ { 𝑥 ∣ 𝜑 } )