Metamath Proof Explorer


Theorem alsbid

Description: Deduction form of alsbii . (Contributed by David A. Wheeler, 12-Jul-2026)

Ref Expression
Hypotheses alsbid.1
|- F/ x ph
alsbid.2
|- ( ph -> ( ps <-> th ) )
alsbid.3
|- ( ph -> ( ch <-> ta ) )
Assertion alsbid
|- ( ph -> ( AE x ( ps -> ch ) <-> AE x ( th -> ta ) ) )

Proof

Step Hyp Ref Expression
1 alsbid.1
 |-  F/ x ph
2 alsbid.2
 |-  ( ph -> ( ps <-> th ) )
3 alsbid.3
 |-  ( ph -> ( ch <-> ta ) )
4 2 3 imbi12d
 |-  ( ph -> ( ( ps -> ch ) <-> ( th -> ta ) ) )
5 1 4 albid
 |-  ( ph -> ( A. x ( ps -> ch ) <-> A. x ( th -> ta ) ) )
6 1 2 exbid
 |-  ( ph -> ( E. x ps <-> E. x th ) )
7 5 6 anbi12d
 |-  ( ph -> ( ( A. x ( ps -> ch ) /\ E. x ps ) <-> ( A. x ( th -> ta ) /\ E. x th ) ) )
8 df-als
 |-  ( AE x ( ps -> ch ) <-> ( A. x ( ps -> ch ) /\ E. x ps ) )
9 df-als
 |-  ( AE x ( th -> ta ) <-> ( A. x ( th -> ta ) /\ E. x th ) )
10 7 8 9 3bitr4g
 |-  ( ph -> ( AE x ( ps -> ch ) <-> AE x ( th -> ta ) ) )