Metamath Proof Explorer


Theorem alsbii

Description: Congruence: equivalents may be substituted inside an "all some". (Contributed by David A. Wheeler, 12-Jul-2026)

Ref Expression
Hypotheses alsbii.1
|- ( ph <-> ch )
alsbii.2
|- ( ps <-> th )
Assertion alsbii
|- ( AE x ( ph -> ps ) <-> AE x ( ch -> th ) )

Proof

Step Hyp Ref Expression
1 alsbii.1
 |-  ( ph <-> ch )
2 alsbii.2
 |-  ( ps <-> th )
3 1 2 imbi12i
 |-  ( ( ph -> ps ) <-> ( ch -> th ) )
4 3 albii
 |-  ( A. x ( ph -> ps ) <-> A. x ( ch -> th ) )
5 1 exbii
 |-  ( E. x ph <-> E. x ch )
6 4 5 anbi12i
 |-  ( ( A. x ( ph -> ps ) /\ E. x ph ) <-> ( A. x ( ch -> th ) /\ E. x ch ) )
7 df-als
 |-  ( AE x ( ph -> ps ) <-> ( A. x ( ph -> ps ) /\ E. x ph ) )
8 df-als
 |-  ( AE x ( ch -> th ) <-> ( A. x ( ch -> th ) /\ E. x ch ) )
9 6 7 8 3bitr4i
 |-  ( AE x ( ph -> ps ) <-> AE x ( ch -> th ) )