Metamath Proof Explorer


Theorem alsbii

Description: Congruence: equivalents may be substituted inside an "all some". (Contributed by David A. Wheeler, 12-Jul-2026)

Ref Expression
Hypotheses alsbii.1 ⊢ ( 𝜑 ↔ 𝜒 )
alsbii.2 ⊢ ( 𝜓 ↔ 𝜃 )
Assertion alsbii ( ∀∃ 𝑥 ( 𝜑 → 𝜓 ) ↔ ∀∃ 𝑥 ( 𝜒 → 𝜃 ) )

Proof

Step Hyp Ref Expression
1 alsbii.1 ⊢ ( 𝜑 ↔ 𝜒 )
2 alsbii.2 ⊢ ( 𝜓 ↔ 𝜃 )
3 1 2 imbi12i ⊢ ( ( 𝜑 → 𝜓 ) ↔ ( 𝜒 → 𝜃 ) )
4 3 albii ⊢ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) ↔ ∀ 𝑥 ( 𝜒 → 𝜃 ) )
5 1 exbii ⊢ ( ∃ 𝑥 𝜑 ↔ ∃ 𝑥 𝜒 )
6 4 5 anbi12i ⊢ ( ( ∀ 𝑥 ( 𝜑 → 𝜓 ) ∧ ∃ 𝑥 𝜑 ) ↔ ( ∀ 𝑥 ( 𝜒 → 𝜃 ) ∧ ∃ 𝑥 𝜒 ) )
7 df-als ⊢ ( ∀∃ 𝑥 ( 𝜑 → 𝜓 ) ↔ ( ∀ 𝑥 ( 𝜑 → 𝜓 ) ∧ ∃ 𝑥 𝜑 ) )
8 df-als ⊢ ( ∀∃ 𝑥 ( 𝜒 → 𝜃 ) ↔ ( ∀ 𝑥 ( 𝜒 → 𝜃 ) ∧ ∃ 𝑥 𝜒 ) )
9 6 7 8 3bitr4i ⊢ ( ∀∃ 𝑥 ( 𝜑 → 𝜓 ) ↔ ∀∃ 𝑥 ( 𝜒 → 𝜃 ) )