Metamath Proof Explorer


Theorem alsbid

Description: Deduction form of alsbii . (Contributed by David A. Wheeler, 12-Jul-2026)

Ref Expression
Hypotheses alsbid.1 𝑥 𝜑
alsbid.2 ( 𝜑 → ( 𝜓𝜃 ) )
alsbid.3 ( 𝜑 → ( 𝜒𝜏 ) )
Assertion alsbid ( 𝜑 → ( ∀∃ 𝑥 ( 𝜓𝜒 ) ↔ ∀∃ 𝑥 ( 𝜃𝜏 ) ) )

Proof

Step Hyp Ref Expression
1 alsbid.1 𝑥 𝜑
2 alsbid.2 ( 𝜑 → ( 𝜓𝜃 ) )
3 alsbid.3 ( 𝜑 → ( 𝜒𝜏 ) )
4 2 3 imbi12d ( 𝜑 → ( ( 𝜓𝜒 ) ↔ ( 𝜃𝜏 ) ) )
5 1 4 albid ( 𝜑 → ( ∀ 𝑥 ( 𝜓𝜒 ) ↔ ∀ 𝑥 ( 𝜃𝜏 ) ) )
6 1 2 exbid ( 𝜑 → ( ∃ 𝑥 𝜓 ↔ ∃ 𝑥 𝜃 ) )
7 5 6 anbi12d ( 𝜑 → ( ( ∀ 𝑥 ( 𝜓𝜒 ) ∧ ∃ 𝑥 𝜓 ) ↔ ( ∀ 𝑥 ( 𝜃𝜏 ) ∧ ∃ 𝑥 𝜃 ) ) )
8 df-als ( ∀∃ 𝑥 ( 𝜓𝜒 ) ↔ ( ∀ 𝑥 ( 𝜓𝜒 ) ∧ ∃ 𝑥 𝜓 ) )
9 df-als ( ∀∃ 𝑥 ( 𝜃𝜏 ) ↔ ( ∀ 𝑥 ( 𝜃𝜏 ) ∧ ∃ 𝑥 𝜃 ) )
10 7 8 9 3bitr4g ( 𝜑 → ( ∀∃ 𝑥 ( 𝜓𝜒 ) ↔ ∀∃ 𝑥 ( 𝜃𝜏 ) ) )