Metamath Proof Explorer


Theorem eq0OLDOLD

Description: Obsolete version of eq0 as of 28-Jun-2024. (Contributed by NM, 29-Aug-1993) (Proof modification is discouraged.) (New usage is discouraged.)

Ref Expression
Assertion eq0OLDOLD
|- ( A = (/) <-> A. x -. x e. A )

Proof

Step Hyp Ref Expression
1 nfcv
 |-  F/_ x A
2 1 eq0f
 |-  ( A = (/) <-> A. x -. x e. A )