Metamath Proof Explorer


Theorem eqnetrd

Description: Substitution of equal classes into an inequality. (Contributed by NM, 4-Jul-2012)

Ref Expression
Hypotheses eqnetrd.1
|- ( ph -> A = B )
eqnetrd.2
|- ( ph -> B =/= C )
Assertion eqnetrd
|- ( ph -> A =/= C )

Proof

Step Hyp Ref Expression
1 eqnetrd.1
 |-  ( ph -> A = B )
2 eqnetrd.2
 |-  ( ph -> B =/= C )
3 1 neeq1d
 |-  ( ph -> ( A =/= C <-> B =/= C ) )
4 2 3 mpbird
 |-  ( ph -> A =/= C )