Metamath Proof Explorer


Theorem equsexh

Description: An equivalence related to implicit substitution. Usage of this theorem is discouraged because it depends on ax-13 . See equsexhv for a version with a disjoint variable condition which does not require ax-13 . (Contributed by NM, 5-Aug-1993) (New usage is discouraged.)

Ref Expression
Hypotheses equsalh.1
|- ( ps -> A. x ps )
equsalh.2
|- ( x = y -> ( ph <-> ps ) )
Assertion equsexh
|- ( E. x ( x = y /\ ph ) <-> ps )

Proof

Step Hyp Ref Expression
1 equsalh.1
 |-  ( ps -> A. x ps )
2 equsalh.2
 |-  ( x = y -> ( ph <-> ps ) )
3 1 nf5i
 |-  F/ x ps
4 3 2 equsex
 |-  ( E. x ( x = y /\ ph ) <-> ps )