Metamath Proof Explorer


Theorem mapdpglem4N

Description: Lemma for mapdpg . (Contributed by NM, 20-Mar-2015) (New usage is discouraged.)

Ref Expression
Hypotheses mapdpglem.h
|- H = ( LHyp ` K )
mapdpglem.m
|- M = ( ( mapd ` K ) ` W )
mapdpglem.u
|- U = ( ( DVecH ` K ) ` W )
mapdpglem.v
|- V = ( Base ` U )
mapdpglem.s
|- .- = ( -g ` U )
mapdpglem.n
|- N = ( LSpan ` U )
mapdpglem.c
|- C = ( ( LCDual ` K ) ` W )
mapdpglem.k
|- ( ph -> ( K e. HL /\ W e. H ) )
mapdpglem.x
|- ( ph -> X e. V )
mapdpglem.y
|- ( ph -> Y e. V )
mapdpglem1.p
|- .(+) = ( LSSum ` C )
mapdpglem2.j
|- J = ( LSpan ` C )
mapdpglem3.f
|- F = ( Base ` C )
mapdpglem3.te
|- ( ph -> t e. ( ( M ` ( N ` { X } ) ) .(+) ( M ` ( N ` { Y } ) ) ) )
mapdpglem3.a
|- A = ( Scalar ` U )
mapdpglem3.b
|- B = ( Base ` A )
mapdpglem3.t
|- .x. = ( .s ` C )
mapdpglem3.r
|- R = ( -g ` C )
mapdpglem3.g
|- ( ph -> G e. F )
mapdpglem3.e
|- ( ph -> ( M ` ( N ` { X } ) ) = ( J ` { G } ) )
mapdpglem4.q
|- Q = ( 0g ` U )
mapdpglem.ne
|- ( ph -> ( N ` { X } ) =/= ( N ` { Y } ) )
Assertion mapdpglem4N
|- ( ph -> ( X .- Y ) =/= Q )

Proof

Step Hyp Ref Expression
1 mapdpglem.h
 |-  H = ( LHyp ` K )
2 mapdpglem.m
 |-  M = ( ( mapd ` K ) ` W )
3 mapdpglem.u
 |-  U = ( ( DVecH ` K ) ` W )
4 mapdpglem.v
 |-  V = ( Base ` U )
5 mapdpglem.s
 |-  .- = ( -g ` U )
6 mapdpglem.n
 |-  N = ( LSpan ` U )
7 mapdpglem.c
 |-  C = ( ( LCDual ` K ) ` W )
8 mapdpglem.k
 |-  ( ph -> ( K e. HL /\ W e. H ) )
9 mapdpglem.x
 |-  ( ph -> X e. V )
10 mapdpglem.y
 |-  ( ph -> Y e. V )
11 mapdpglem1.p
 |-  .(+) = ( LSSum ` C )
12 mapdpglem2.j
 |-  J = ( LSpan ` C )
13 mapdpglem3.f
 |-  F = ( Base ` C )
14 mapdpglem3.te
 |-  ( ph -> t e. ( ( M ` ( N ` { X } ) ) .(+) ( M ` ( N ` { Y } ) ) ) )
15 mapdpglem3.a
 |-  A = ( Scalar ` U )
16 mapdpglem3.b
 |-  B = ( Base ` A )
17 mapdpglem3.t
 |-  .x. = ( .s ` C )
18 mapdpglem3.r
 |-  R = ( -g ` C )
19 mapdpglem3.g
 |-  ( ph -> G e. F )
20 mapdpglem3.e
 |-  ( ph -> ( M ` ( N ` { X } ) ) = ( J ` { G } ) )
21 mapdpglem4.q
 |-  Q = ( 0g ` U )
22 mapdpglem.ne
 |-  ( ph -> ( N ` { X } ) =/= ( N ` { Y } ) )
23 1 3 8 dvhlmod
 |-  ( ph -> U e. LMod )
24 4 21 5 23 9 10 22 lspsnsubn0
 |-  ( ph -> ( X .- Y ) =/= Q )