Metamath Proof Explorer


Theorem oppgbas

Description: Base set of an opposite group. (Contributed by Stefan O'Rear, 26-Aug-2015)

Ref Expression
Hypotheses oppgbas.1
|- O = ( oppG ` R )
oppgbas.2
|- B = ( Base ` R )
Assertion oppgbas
|- B = ( Base ` O )

Proof

Step Hyp Ref Expression
1 oppgbas.1
 |-  O = ( oppG ` R )
2 oppgbas.2
 |-  B = ( Base ` R )
3 df-base
 |-  Base = Slot 1
4 1nn
 |-  1 e. NN
5 1ne2
 |-  1 =/= 2
6 1 3 4 5 oppglem
 |-  ( Base ` R ) = ( Base ` O )
7 2 6 eqtri
 |-  B = ( Base ` O )