Metamath Proof Explorer


Theorem oppgbas

Description: Base set of an opposite group. (Contributed by Stefan O'Rear, 26-Aug-2015)

Ref Expression
Hypotheses oppgbas.1 𝑂 = ( oppg𝑅 )
oppgbas.2 𝐵 = ( Base ‘ 𝑅 )
Assertion oppgbas 𝐵 = ( Base ‘ 𝑂 )

Proof

Step Hyp Ref Expression
1 oppgbas.1 𝑂 = ( oppg𝑅 )
2 oppgbas.2 𝐵 = ( Base ‘ 𝑅 )
3 df-base Base = Slot 1
4 1nn 1 ∈ ℕ
5 1ne2 1 ≠ 2
6 1 3 4 5 oppglem ( Base ‘ 𝑅 ) = ( Base ‘ 𝑂 )
7 2 6 eqtri 𝐵 = ( Base ‘ 𝑂 )