Metamath Proof Explorer


Theorem psseq2

Description: Equality theorem for proper subclass. (Contributed by NM, 7-Feb-1996)

Ref Expression
Assertion psseq2
|- ( A = B -> ( C C. A <-> C C. B ) )

Proof

Step Hyp Ref Expression
1 sseq2
 |-  ( A = B -> ( C C_ A <-> C C_ B ) )
2 neeq2
 |-  ( A = B -> ( C =/= A <-> C =/= B ) )
3 1 2 anbi12d
 |-  ( A = B -> ( ( C C_ A /\ C =/= A ) <-> ( C C_ B /\ C =/= B ) ) )
4 df-pss
 |-  ( C C. A <-> ( C C_ A /\ C =/= A ) )
5 df-pss
 |-  ( C C. B <-> ( C C_ B /\ C =/= B ) )
6 3 4 5 3bitr4g
 |-  ( A = B -> ( C C. A <-> C C. B ) )