Metamath Proof Explorer


Theorem rngqipbas

Description: The base set of the product of the quotient with a two-sided ideal and the two-sided ideal is the cartesian product of the base set of the quotient and the base set of the two-sided ideal. (Contributed by AV, 21-Feb-2025)

Ref Expression
Hypotheses rng2idlring.r
|- ( ph -> R e. Rng )
rng2idlring.i
|- ( ph -> I e. ( 2Ideal ` R ) )
rng2idlring.j
|- J = ( R |`s I )
rng2idlring.u
|- ( ph -> J e. Ring )
rng2idlring.b
|- B = ( Base ` R )
rng2idlring.t
|- .x. = ( .r ` R )
rng2idlring.1
|- .1. = ( 1r ` J )
rngqiprngim.g
|- .~ = ( R ~QG I )
rngqiprngim.q
|- Q = ( R /s .~ )
rngqiprngim.c
|- C = ( Base ` Q )
rngqiprngim.p
|- P = ( Q Xs. J )
Assertion rngqipbas
|- ( ph -> ( Base ` P ) = ( C X. I ) )

Proof

Step Hyp Ref Expression
1 rng2idlring.r
 |-  ( ph -> R e. Rng )
2 rng2idlring.i
 |-  ( ph -> I e. ( 2Ideal ` R ) )
3 rng2idlring.j
 |-  J = ( R |`s I )
4 rng2idlring.u
 |-  ( ph -> J e. Ring )
5 rng2idlring.b
 |-  B = ( Base ` R )
6 rng2idlring.t
 |-  .x. = ( .r ` R )
7 rng2idlring.1
 |-  .1. = ( 1r ` J )
8 rngqiprngim.g
 |-  .~ = ( R ~QG I )
9 rngqiprngim.q
 |-  Q = ( R /s .~ )
10 rngqiprngim.c
 |-  C = ( Base ` Q )
11 rngqiprngim.p
 |-  P = ( Q Xs. J )
12 eqid
 |-  ( Base ` J ) = ( Base ` J )
13 9 ovexi
 |-  Q e. _V
14 13 a1i
 |-  ( ph -> Q e. _V )
15 11 10 12 14 4 xpsbas
 |-  ( ph -> ( C X. ( Base ` J ) ) = ( Base ` P ) )
16 2 3 12 2idlbas
 |-  ( ph -> ( Base ` J ) = I )
17 16 xpeq2d
 |-  ( ph -> ( C X. ( Base ` J ) ) = ( C X. I ) )
18 15 17 eqtr3d
 |-  ( ph -> ( Base ` P ) = ( C X. I ) )