Metamath Proof Explorer


Theorem rngqipbas

Description: The base set of the product of the quotient with a two-sided ideal and the two-sided ideal is the cartesian product of the base set of the quotient and the base set of the two-sided ideal. (Contributed by AV, 21-Feb-2025)

Ref Expression
Hypotheses rng2idlring.r ( 𝜑𝑅 ∈ Rng )
rng2idlring.i ( 𝜑𝐼 ∈ ( 2Ideal ‘ 𝑅 ) )
rng2idlring.j 𝐽 = ( 𝑅s 𝐼 )
rng2idlring.u ( 𝜑𝐽 ∈ Ring )
rng2idlring.b 𝐵 = ( Base ‘ 𝑅 )
rng2idlring.t · = ( .r𝑅 )
rng2idlring.1 1 = ( 1r𝐽 )
rngqiprngim.g = ( 𝑅 ~QG 𝐼 )
rngqiprngim.q 𝑄 = ( 𝑅 /s )
rngqiprngim.c 𝐶 = ( Base ‘ 𝑄 )
rngqiprngim.p 𝑃 = ( 𝑄 ×s 𝐽 )
Assertion rngqipbas ( 𝜑 → ( Base ‘ 𝑃 ) = ( 𝐶 × 𝐼 ) )

Proof

Step Hyp Ref Expression
1 rng2idlring.r ( 𝜑𝑅 ∈ Rng )
2 rng2idlring.i ( 𝜑𝐼 ∈ ( 2Ideal ‘ 𝑅 ) )
3 rng2idlring.j 𝐽 = ( 𝑅s 𝐼 )
4 rng2idlring.u ( 𝜑𝐽 ∈ Ring )
5 rng2idlring.b 𝐵 = ( Base ‘ 𝑅 )
6 rng2idlring.t · = ( .r𝑅 )
7 rng2idlring.1 1 = ( 1r𝐽 )
8 rngqiprngim.g = ( 𝑅 ~QG 𝐼 )
9 rngqiprngim.q 𝑄 = ( 𝑅 /s )
10 rngqiprngim.c 𝐶 = ( Base ‘ 𝑄 )
11 rngqiprngim.p 𝑃 = ( 𝑄 ×s 𝐽 )
12 eqid ( Base ‘ 𝐽 ) = ( Base ‘ 𝐽 )
13 9 ovexi 𝑄 ∈ V
14 13 a1i ( 𝜑𝑄 ∈ V )
15 11 10 12 14 4 xpsbas ( 𝜑 → ( 𝐶 × ( Base ‘ 𝐽 ) ) = ( Base ‘ 𝑃 ) )
16 2 3 12 2idlbas ( 𝜑 → ( Base ‘ 𝐽 ) = 𝐼 )
17 16 xpeq2d ( 𝜑 → ( 𝐶 × ( Base ‘ 𝐽 ) ) = ( 𝐶 × 𝐼 ) )
18 15 17 eqtr3d ( 𝜑 → ( Base ‘ 𝑃 ) = ( 𝐶 × 𝐼 ) )