Description: The base set of the product of the quotient with a two-sided ideal and the two-sided ideal is the cartesian product of the base set of the quotient and the base set of the two-sided ideal. (Contributed by AV, 21-Feb-2025)
Ref | Expression | ||
---|---|---|---|
Hypotheses | rng2idlring.r | ⊢ ( 𝜑 → 𝑅 ∈ Rng ) | |
rng2idlring.i | ⊢ ( 𝜑 → 𝐼 ∈ ( 2Ideal ‘ 𝑅 ) ) | ||
rng2idlring.j | ⊢ 𝐽 = ( 𝑅 ↾s 𝐼 ) | ||
rng2idlring.u | ⊢ ( 𝜑 → 𝐽 ∈ Ring ) | ||
rng2idlring.b | ⊢ 𝐵 = ( Base ‘ 𝑅 ) | ||
rng2idlring.t | ⊢ · = ( .r ‘ 𝑅 ) | ||
rng2idlring.1 | ⊢ 1 = ( 1r ‘ 𝐽 ) | ||
rngqiprngim.g | ⊢ ∼ = ( 𝑅 ~QG 𝐼 ) | ||
rngqiprngim.q | ⊢ 𝑄 = ( 𝑅 /s ∼ ) | ||
rngqiprngim.c | ⊢ 𝐶 = ( Base ‘ 𝑄 ) | ||
rngqiprngim.p | ⊢ 𝑃 = ( 𝑄 ×s 𝐽 ) | ||
Assertion | rngqipbas | ⊢ ( 𝜑 → ( Base ‘ 𝑃 ) = ( 𝐶 × 𝐼 ) ) |
Step | Hyp | Ref | Expression |
---|---|---|---|
1 | rng2idlring.r | ⊢ ( 𝜑 → 𝑅 ∈ Rng ) | |
2 | rng2idlring.i | ⊢ ( 𝜑 → 𝐼 ∈ ( 2Ideal ‘ 𝑅 ) ) | |
3 | rng2idlring.j | ⊢ 𝐽 = ( 𝑅 ↾s 𝐼 ) | |
4 | rng2idlring.u | ⊢ ( 𝜑 → 𝐽 ∈ Ring ) | |
5 | rng2idlring.b | ⊢ 𝐵 = ( Base ‘ 𝑅 ) | |
6 | rng2idlring.t | ⊢ · = ( .r ‘ 𝑅 ) | |
7 | rng2idlring.1 | ⊢ 1 = ( 1r ‘ 𝐽 ) | |
8 | rngqiprngim.g | ⊢ ∼ = ( 𝑅 ~QG 𝐼 ) | |
9 | rngqiprngim.q | ⊢ 𝑄 = ( 𝑅 /s ∼ ) | |
10 | rngqiprngim.c | ⊢ 𝐶 = ( Base ‘ 𝑄 ) | |
11 | rngqiprngim.p | ⊢ 𝑃 = ( 𝑄 ×s 𝐽 ) | |
12 | eqid | ⊢ ( Base ‘ 𝐽 ) = ( Base ‘ 𝐽 ) | |
13 | 9 | ovexi | ⊢ 𝑄 ∈ V |
14 | 13 | a1i | ⊢ ( 𝜑 → 𝑄 ∈ V ) |
15 | 11 10 12 14 4 | xpsbas | ⊢ ( 𝜑 → ( 𝐶 × ( Base ‘ 𝐽 ) ) = ( Base ‘ 𝑃 ) ) |
16 | 2 3 12 | 2idlbas | ⊢ ( 𝜑 → ( Base ‘ 𝐽 ) = 𝐼 ) |
17 | 16 | xpeq2d | ⊢ ( 𝜑 → ( 𝐶 × ( Base ‘ 𝐽 ) ) = ( 𝐶 × 𝐼 ) ) |
18 | 15 17 | eqtr3d | ⊢ ( 𝜑 → ( Base ‘ 𝑃 ) = ( 𝐶 × 𝐼 ) ) |