Metamath Proof Explorer


Theorem xpsbas

Description: The base set of the binary structure product. (Contributed by Mario Carneiro, 15-Aug-2015)

Ref Expression
Hypotheses xpsval.t 𝑇 = ( 𝑅 ×s 𝑆 )
xpsval.x 𝑋 = ( Base ‘ 𝑅 )
xpsval.y 𝑌 = ( Base ‘ 𝑆 )
xpsval.1 ( 𝜑𝑅𝑉 )
xpsval.2 ( 𝜑𝑆𝑊 )
Assertion xpsbas ( 𝜑 → ( 𝑋 × 𝑌 ) = ( Base ‘ 𝑇 ) )

Proof

Step Hyp Ref Expression
1 xpsval.t 𝑇 = ( 𝑅 ×s 𝑆 )
2 xpsval.x 𝑋 = ( Base ‘ 𝑅 )
3 xpsval.y 𝑌 = ( Base ‘ 𝑆 )
4 xpsval.1 ( 𝜑𝑅𝑉 )
5 xpsval.2 ( 𝜑𝑆𝑊 )
6 eqid ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) = ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } )
7 eqid ( Scalar ‘ 𝑅 ) = ( Scalar ‘ 𝑅 )
8 eqid ( ( Scalar ‘ 𝑅 ) Xs { ⟨ ∅ , 𝑅 ⟩ , ⟨ 1o , 𝑆 ⟩ } ) = ( ( Scalar ‘ 𝑅 ) Xs { ⟨ ∅ , 𝑅 ⟩ , ⟨ 1o , 𝑆 ⟩ } )
9 1 2 3 4 5 6 7 8 xpsval ( 𝜑𝑇 = ( ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) “s ( ( Scalar ‘ 𝑅 ) Xs { ⟨ ∅ , 𝑅 ⟩ , ⟨ 1o , 𝑆 ⟩ } ) ) )
10 1 2 3 4 5 6 7 8 xpsrnbas ( 𝜑 → ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) = ( Base ‘ ( ( Scalar ‘ 𝑅 ) Xs { ⟨ ∅ , 𝑅 ⟩ , ⟨ 1o , 𝑆 ⟩ } ) ) )
11 6 xpsff1o2 ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) : ( 𝑋 × 𝑌 ) –1-1-onto→ ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } )
12 f1ocnv ( ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) : ( 𝑋 × 𝑌 ) –1-1-onto→ ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) → ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) : ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) –1-1-onto→ ( 𝑋 × 𝑌 ) )
13 11 12 ax-mp ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) : ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) –1-1-onto→ ( 𝑋 × 𝑌 )
14 f1ofo ( ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) : ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) –1-1-onto→ ( 𝑋 × 𝑌 ) → ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) : ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) –onto→ ( 𝑋 × 𝑌 ) )
15 13 14 mp1i ( 𝜑 ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) : ran ( 𝑥𝑋 , 𝑦𝑌 ↦ { ⟨ ∅ , 𝑥 ⟩ , ⟨ 1o , 𝑦 ⟩ } ) –onto→ ( 𝑋 × 𝑌 ) )
16 ovexd ( 𝜑 → ( ( Scalar ‘ 𝑅 ) Xs { ⟨ ∅ , 𝑅 ⟩ , ⟨ 1o , 𝑆 ⟩ } ) ∈ V )
17 9 10 15 16 imasbas ( 𝜑 → ( 𝑋 × 𝑌 ) = ( Base ‘ 𝑇 ) )