Metamath Proof Explorer


Theorem sbid

Description: An identity theorem for substitution. Remark 9.1 in Megill p. 447 (p. 15 of the preprint). (Contributed by NM, 26-May-1993) (Proof shortened by Wolf Lammen, 30-Sep-2018)

Ref Expression
Assertion sbid
|- ( [ x / x ] ph <-> ph )

Proof

Step Hyp Ref Expression
1 equid
 |-  x = x
2 sbequ12r
 |-  ( x = x -> ( [ x / x ] ph <-> ph ) )
3 1 2 ax-mp
 |-  ( [ x / x ] ph <-> ph )