Metamath Proof Explorer


Theorem 0dig1

Description: The 0 th digit of 1 is 1 in any positional system. (Contributed by AV, 28-May-2020)

Ref Expression
Assertion 0dig1 ⊢ B ∈ ℤ ≥ 2 → 0 digit ⁡ B 1 = 1

Proof

Step Hyp Ref Expression
1 0z ⊢ 0 ∈ ℤ
2 dig1 ⊢ B ∈ ℤ ≥ 2 ∧ 0 ∈ ℤ → 0 digit ⁡ B 1 = if 0 = 0 1 0
3 1 2 mpan2 ⊢ B ∈ ℤ ≥ 2 → 0 digit ⁡ B 1 = if 0 = 0 1 0
4 eqid ⊢ 0 = 0
5 4 iftruei ⊢ if 0 = 0 1 0 = 1
6 3 5 eqtrdi ⊢ B ∈ ℤ ≥ 2 → 0 digit ⁡ B 1 = 1