Metamath Proof Explorer


Theorem 0dig2pr01

Description: The integers 0 and 1 correspond to their last bit. (Contributed by AV, 28-May-2010)

Ref Expression
Assertion 0dig2pr01 ⊢ N ∈ 0 1 → 0 digit ⁡ 2 N = N

Proof

Step Hyp Ref Expression
1 elpri ⊢ N ∈ 0 1 → N = 0 ∨ N = 1
2 2nn ⊢ 2 ∈ ℕ
3 0z ⊢ 0 ∈ ℤ
4 dig0 ⊢ 2 ∈ ℕ ∧ 0 ∈ ℤ → 0 digit ⁡ 2 0 = 0
5 2 3 4 mp2an ⊢ 0 digit ⁡ 2 0 = 0
6 oveq2 ⊢ N = 0 → 0 digit ⁡ 2 N = 0 digit ⁡ 2 0
7 id ⊢ N = 0 → N = 0
8 5 6 7 3eqtr4a ⊢ N = 0 → 0 digit ⁡ 2 N = N
9 2z ⊢ 2 ∈ ℤ
10 uzid ⊢ 2 ∈ ℤ → 2 ∈ ℤ ≥ 2
11 0dig1 ⊢ 2 ∈ ℤ ≥ 2 → 0 digit ⁡ 2 1 = 1
12 9 10 11 mp2b ⊢ 0 digit ⁡ 2 1 = 1
13 oveq2 ⊢ N = 1 → 0 digit ⁡ 2 N = 0 digit ⁡ 2 1
14 id ⊢ N = 1 → N = 1
15 12 13 14 3eqtr4a ⊢ N = 1 → 0 digit ⁡ 2 N = N
16 8 15 jaoi ⊢ N = 0 ∨ N = 1 → 0 digit ⁡ 2 N = N
17 1 16 syl ⊢ N ∈ 0 1 → 0 digit ⁡ 2 N = N