Metamath Proof Explorer


Theorem 0re

Description: The number 0 is real. Remark: the first step could also be ax-icn . See also 0reALT . (Contributed by Eric Schmidt, 21-May-2007) (Revised by Scott Fenton, 3-Jan-2013) Reduce dependencies on axioms. (Revised by Steven Nguyen, 11-Oct-2022)

Ref Expression
Assertion 0re ⊢ 0 ∈ ℝ

Proof

Step Hyp Ref Expression
1 ax-1cn ⊢ 1 ∈ ℂ
2 cnre ⊢ 1 ∈ ℂ → ∃ x ∈ ℝ ∃ y ∈ ℝ 1 = x + i ⁢ y
3 ax-rnegex ⊢ x ∈ ℝ → ∃ z ∈ ℝ x + z = 0
4 readdcl ⊢ x ∈ ℝ ∧ z ∈ ℝ → x + z ∈ ℝ
5 eleq1 ⊢ x + z = 0 → x + z ∈ ℝ ↔ 0 ∈ ℝ
6 4 5 syl5ibcom ⊢ x ∈ ℝ ∧ z ∈ ℝ → x + z = 0 → 0 ∈ ℝ
7 6 rexlimdva ⊢ x ∈ ℝ → ∃ z ∈ ℝ x + z = 0 → 0 ∈ ℝ
8 3 7 mpd ⊢ x ∈ ℝ → 0 ∈ ℝ
9 8 adantr ⊢ x ∈ ℝ ∧ ∃ y ∈ ℝ 1 = x + i ⁢ y → 0 ∈ ℝ
10 9 rexlimiva ⊢ ∃ x ∈ ℝ ∃ y ∈ ℝ 1 = x + i ⁢ y → 0 ∈ ℝ
11 1 2 10 mp2b ⊢ 0 ∈ ℝ