Metamath Proof Explorer


Theorem 19.12vv

Description: Special case of 19.12 where its converse holds. See 19.12vvv for a version with a disjoint variable condition requiring fewer axioms. (Contributed by NM, 18-Jul-2001) (Revised by Andrew Salmon, 11-Jul-2011)

Ref Expression
Assertion 19.12vv ⊢ ∃ x ∀ y φ → ψ ↔ ∀ y ∃ x φ → ψ

Proof

Step Hyp Ref Expression
1 19.21v ⊢ ∀ y φ → ψ ↔ φ → ∀ y ψ
2 1 exbii ⊢ ∃ x ∀ y φ → ψ ↔ ∃ x φ → ∀ y ψ
3 nfv ⊢ Ⅎ x ψ
4 3 nfal ⊢ Ⅎ x ∀ y ψ
5 4 19.36 ⊢ ∃ x φ → ∀ y ψ ↔ ∀ x φ → ∀ y ψ
6 19.36v ⊢ ∃ x φ → ψ ↔ ∀ x φ → ψ
7 6 albii ⊢ ∀ y ∃ x φ → ψ ↔ ∀ y ∀ x φ → ψ
8 nfv ⊢ Ⅎ y φ
9 8 nfal ⊢ Ⅎ y ∀ x φ
10 9 19.21 ⊢ ∀ y ∀ x φ → ψ ↔ ∀ x φ → ∀ y ψ
11 7 10 bitr2i ⊢ ∀ x φ → ∀ y ψ ↔ ∀ y ∃ x φ → ψ
12 2 5 11 3bitri ⊢ ∃ x ∀ y φ → ψ ↔ ∀ y ∃ x φ → ψ