Metamath Proof Explorer


Theorem 1oaomeqom

Description: Ordinal one plus omega is equal to omega. See oaabs for the sum of any natural number on the left and ordinal at least as large as omega on the right. Lemma 3.8 of Schloeder p. 8. See oaabs2 where a power of omega is the upper bound of the left and a lower bound on the right. (Contributed by RP, 29-Jan-2025)

Ref Expression
Assertion 1oaomeqom 1𝑜+𝑜ω=ω

Proof

Step Hyp Ref Expression
1 omelon ωOn
2 1onn 1𝑜ω
3 oaabslem ωOn1𝑜ω1𝑜+𝑜ω=ω
4 1 2 3 mp2an 1𝑜+𝑜ω=ω