Metamath Proof Explorer


Theorem 3jca

Description: Join consequents with conjunction. (Contributed by NM, 9-Apr-1994)

Ref Expression
Hypotheses 3jca.1 ⊢ φ → ψ
3jca.2 ⊢ φ → χ
3jca.3 ⊢ φ → θ
Assertion 3jca ⊢ φ → ψ ∧ χ ∧ θ

Proof

Step Hyp Ref Expression
1 3jca.1 ⊢ φ → ψ
2 3jca.2 ⊢ φ → χ
3 3jca.3 ⊢ φ → θ
4 1 2 3 jca31 ⊢ φ → ψ ∧ χ ∧ θ
5 df-3an ⊢ ψ ∧ χ ∧ θ ↔ ψ ∧ χ ∧ θ
6 4 5 sylibr ⊢ φ → ψ ∧ χ ∧ θ