Metamath Proof Explorer


Theorem 3oalem4

Description: Lemma for 3OA (weak) orthoarguesian law. (Contributed by NM, 19-Oct-1999) (New usage is discouraged.)

Ref Expression
Hypothesis 3oalem4.3 ⊢ R = ⊥ ⁡ B ∩ B ∨ ℋ A
Assertion 3oalem4 ⊢ R ⊆ ⊥ ⁡ B

Proof

Step Hyp Ref Expression
1 3oalem4.3 ⊢ R = ⊥ ⁡ B ∩ B ∨ ℋ A
2 inss1 ⊢ ⊥ ⁡ B ∩ B ∨ ℋ A ⊆ ⊥ ⁡ B
3 1 2 eqsstri ⊢ R ⊆ ⊥ ⁡ B