Metamath Proof Explorer
Description: Lemma for 3OA (weak) orthoarguesian law. (Contributed by NM, 19-Oct-1999) (New usage is discouraged.)
|
|
Ref |
Expression |
|
Hypothesis |
3oalem4.3 |
⊢ 𝑅 = ( ( ⊥ ‘ 𝐵 ) ∩ ( 𝐵 ∨ℋ 𝐴 ) ) |
|
Assertion |
3oalem4 |
⊢ 𝑅 ⊆ ( ⊥ ‘ 𝐵 ) |
Proof
Step |
Hyp |
Ref |
Expression |
1 |
|
3oalem4.3 |
⊢ 𝑅 = ( ( ⊥ ‘ 𝐵 ) ∩ ( 𝐵 ∨ℋ 𝐴 ) ) |
2 |
|
inss1 |
⊢ ( ( ⊥ ‘ 𝐵 ) ∩ ( 𝐵 ∨ℋ 𝐴 ) ) ⊆ ( ⊥ ‘ 𝐵 ) |
3 |
1 2
|
eqsstri |
⊢ 𝑅 ⊆ ( ⊥ ‘ 𝐵 ) |