Metamath Proof Explorer


Theorem 8th4div3

Description: An eighth of four thirds is a sixth. (Contributed by Paul Chapman, 24-Nov-2007)

Ref Expression
Assertion 8th4div3 ⊢ 1 8 ⁢ 4 3 = 1 6

Proof

Step Hyp Ref Expression
1 ax-1cn ⊢ 1 ∈ ℂ
2 8cn ⊢ 8 ∈ ℂ
3 4cn ⊢ 4 ∈ ℂ
4 3cn ⊢ 3 ∈ ℂ
5 8re ⊢ 8 ∈ ℝ
6 8pos ⊢ 0 < 8
7 5 6 gt0ne0ii ⊢ 8 ≠ 0
8 3ne0 ⊢ 3 ≠ 0
9 1 2 3 4 7 8 divmuldivi ⊢ 1 8 ⁢ 4 3 = 1 ⋅ 4 8 ⋅ 3
10 1 3 mulcomi ⊢ 1 ⋅ 4 = 4 ⋅ 1
11 2cn ⊢ 2 ∈ ℂ
12 3 11 4 mulassi ⊢ 4 ⋅ 2 ⋅ 3 = 4 ⁢ 2 ⋅ 3
13 4t2e8 ⊢ 4 ⋅ 2 = 8
14 13 oveq1i ⊢ 4 ⋅ 2 ⋅ 3 = 8 ⋅ 3
15 2t3e6 ⊢ 2 ⋅ 3 = 6
16 15 oveq2i ⊢ 4 ⁢ 2 ⋅ 3 = 4 ⋅ 6
17 12 14 16 3eqtr3i ⊢ 8 ⋅ 3 = 4 ⋅ 6
18 10 17 oveq12i ⊢ 1 ⋅ 4 8 ⋅ 3 = 4 ⋅ 1 4 ⋅ 6
19 9 18 eqtri ⊢ 1 8 ⁢ 4 3 = 4 ⋅ 1 4 ⋅ 6
20 6cn ⊢ 6 ∈ ℂ
21 6re ⊢ 6 ∈ ℝ
22 6pos ⊢ 0 < 6
23 21 22 gt0ne0ii ⊢ 6 ≠ 0
24 4ne0 ⊢ 4 ≠ 0
25 divcan5 ⊢ 1 ∈ ℂ ∧ 6 ∈ ℂ ∧ 6 ≠ 0 ∧ 4 ∈ ℂ ∧ 4 ≠ 0 → 4 ⋅ 1 4 ⋅ 6 = 1 6
26 1 25 mp3an1 ⊢ 6 ∈ ℂ ∧ 6 ≠ 0 ∧ 4 ∈ ℂ ∧ 4 ≠ 0 → 4 ⋅ 1 4 ⋅ 6 = 1 6
27 20 23 3 24 26 mp4an ⊢ 4 ⋅ 1 4 ⋅ 6 = 1 6
28 19 27 eqtri ⊢ 1 8 ⁢ 4 3 = 1 6