Metamath Proof Explorer


Theorem 8th4div3

Description: An eighth of four thirds is a sixth. (Contributed by Paul Chapman, 24-Nov-2007)

Ref Expression
Assertion 8th4div3 1 8 4 3 = 1 6

Proof

Step Hyp Ref Expression
1 ax-1cn 1
2 8cn 8
3 4cn 4
4 3cn 3
5 8re 8
6 8pos 0 < 8
7 5 6 gt0ne0ii 8 0
8 3ne0 3 0
9 1 2 3 4 7 8 divmuldivi 1 8 4 3 = 1 4 8 3
10 1 3 mulcomi 1 4 = 4 1
11 2cn 2
12 3 11 4 mulassi 4 2 3 = 4 2 3
13 4t2e8 4 2 = 8
14 13 oveq1i 4 2 3 = 8 3
15 2t3e6 2 3 = 6
16 15 oveq2i 4 2 3 = 4 6
17 12 14 16 3eqtr3i 8 3 = 4 6
18 10 17 oveq12i 1 4 8 3 = 4 1 4 6
19 9 18 eqtri 1 8 4 3 = 4 1 4 6
20 6cn 6
21 6re 6
22 6pos 0 < 6
23 21 22 gt0ne0ii 6 0
24 4ne0 4 0
25 divcan5 1 6 6 0 4 4 0 4 1 4 6 = 1 6
26 1 25 mp3an1 6 6 0 4 4 0 4 1 4 6 = 1 6
27 20 23 3 24 26 mp4an 4 1 4 6 = 1 6
28 19 27 eqtri 1 8 4 3 = 1 6