Metamath Proof Explorer


Theorem absexpd

Description: Absolute value of positive integer exponentiation. (Contributed by Mario Carneiro, 29-May-2016)

Ref Expression
Hypotheses abscld.1 ⊢ φ → A ∈ ℂ
absexpd.2 ⊢ φ → N ∈ ℕ 0
Assertion absexpd ⊢ φ → A N = A N

Proof

Step Hyp Ref Expression
1 abscld.1 ⊢ φ → A ∈ ℂ
2 absexpd.2 ⊢ φ → N ∈ ℕ 0
3 absexp ⊢ A ∈ ℂ ∧ N ∈ ℕ 0 → A N = A N
4 1 2 3 syl2anc ⊢ φ → A N = A N