Metamath Proof Explorer


Theorem absnw

Description: Replace ax-10 , ax-11 , ax-12 in absn with a substitution hypothesis. (Contributed by SN, 27-May-2025)

Ref Expression
Hypothesis absnw.y ⊢ x = y → φ ↔ ψ
Assertion absnw ⊢ x | φ = Y ↔ ∀ x φ ↔ x = Y

Proof

Step Hyp Ref Expression
1 absnw.y ⊢ x = y → φ ↔ ψ
2 df-sn ⊢ Y = x | x = Y
3 2 eqeq2i ⊢ x | φ = Y ↔ x | φ = x | x = Y
4 eqeq1 ⊢ x = y → x = Y ↔ y = Y
5 1 4 abbibw ⊢ x | φ = x | x = Y ↔ ∀ x φ ↔ x = Y
6 3 5 bitri ⊢ x | φ = Y ↔ ∀ x φ ↔ x = Y