Metamath Proof Explorer


Theorem absscl

Description: Closure law for surreal absolute value. (Contributed by Scott Fenton, 16-Apr-2025)

Ref Expression
Assertion absscl ⊢ A ∈ No → abs s ⁡ A ∈ No

Proof

Step Hyp Ref Expression
1 abssval ⊢ A ∈ No → abs s ⁡ A = if 0 s ≤ s A A + s ⁡ A
2 id ⊢ A ∈ No → A ∈ No
3 negscl ⊢ A ∈ No → + s ⁡ A ∈ No
4 2 3 ifcld ⊢ A ∈ No → if 0 s ≤ s A A + s ⁡ A ∈ No
5 1 4 eqeltrd ⊢ A ∈ No → abs s ⁡ A ∈ No