Metamath Proof Explorer


Theorem abssval

Description: The value of surreal absolute value. (Contributed by Scott Fenton, 16-Apr-2025)

Ref Expression
Assertion abssval ⊢ A ∈ No → abs s ⁡ A = if 0 s ≤ s A A + s ⁡ A

Proof

Step Hyp Ref Expression
1 df-abss ⊢ abs s = x ∈ No ⟼ if 0 s ≤ s x x + s ⁡ x
2 breq2 ⊢ x = A → 0 s ≤ s x ↔ 0 s ≤ s A
3 id ⊢ x = A → x = A
4 fveq2 ⊢ x = A → + s ⁡ x = + s ⁡ A
5 2 3 4 ifbieq12d ⊢ x = A → if 0 s ≤ s x x + s ⁡ x = if 0 s ≤ s A A + s ⁡ A
6 id ⊢ A ∈ No → A ∈ No
7 negscl ⊢ A ∈ No → + s ⁡ A ∈ No
8 6 7 ifcld ⊢ A ∈ No → if 0 s ≤ s A A + s ⁡ A ∈ No
9 1 5 6 8 fvmptd3 ⊢ A ∈ No → abs s ⁡ A = if 0 s ≤ s A A + s ⁡ A