Metamath Proof Explorer


Theorem absval

Description: The absolute value (modulus) of a complex number. Proposition 10-3.7(a) of Gleason p. 133. (Contributed by NM, 27-Jul-1999) (Revised by Mario Carneiro, 7-Nov-2013)

Ref Expression
Assertion absval ⊢ A ∈ ℂ → A = A ⁢ A ‾

Proof

Step Hyp Ref Expression
1 fveq2 ⊢ x = A → x ‾ = A ‾
2 oveq12 ⊢ x = A ∧ x ‾ = A ‾ → x ⁢ x ‾ = A ⁢ A ‾
3 1 2 mpdan ⊢ x = A → x ⁢ x ‾ = A ⁢ A ‾
4 3 fveq2d ⊢ x = A → x ⁢ x ‾ = A ⁢ A ‾
5 df-abs ⊢ abs = x ∈ ℂ ⟼ x ⁢ x ‾
6 fvex ⊢ A ⁢ A ‾ ∈ V
7 4 5 6 fvmpt ⊢ A ∈ ℂ → A = A ⁢ A ‾