Metamath Proof Explorer


Theorem absvalsq

Description: Square of value of absolute value function. (Contributed by NM, 16-Jan-2006)

Ref Expression
Assertion absvalsq ⊢ A ∈ ℂ → A 2 = A ⁢ A ‾

Proof

Step Hyp Ref Expression
1 absval ⊢ A ∈ ℂ → A = A ⁢ A ‾
2 1 oveq1d ⊢ A ∈ ℂ → A 2 = A ⁢ A ‾ 2
3 cjmulrcl ⊢ A ∈ ℂ → A ⁢ A ‾ ∈ ℝ
4 cjmulge0 ⊢ A ∈ ℂ → 0 ≤ A ⁢ A ‾
5 resqrtth ⊢ A ⁢ A ‾ ∈ ℝ ∧ 0 ≤ A ⁢ A ‾ → A ⁢ A ‾ 2 = A ⁢ A ‾
6 3 4 5 syl2anc ⊢ A ∈ ℂ → A ⁢ A ‾ 2 = A ⁢ A ‾
7 2 6 eqtrd ⊢ A ∈ ℂ → A 2 = A ⁢ A ‾